Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-One marble is white and one marble is blue.
A) $\frac { 3 } { 28 }$
B) $\frac { 1 } { 2 }$
C) $\frac { 3 } { 56 }$
D) $\frac { 1 } { 4 }$

Question

Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability.
-One marble is white and one marble is blue. 
A) $\frac { 3 } { 28 }$
B) $\frac { 1 } { 2 }$
C) $\frac { 3 } { 56 }$
D) $\frac { 1 } { 4 }$

Quizplus · Accepted Answer

The probability of drawing a white marble first is $\frac{3}{8}$, and then drawing a blue marble is $\frac{1}{7}$. Alternatively, drawing a blue marble first is $\frac{1}{8}$, and then a white marble is $\frac{3}{7}$. Adding these probabilities gives $\frac{3}{56} + \frac{3}{56} = \frac{3}{28}$.

Two Marbles Are Drawn Without Replacement from a Box with 3