Perform the indicated operations.
-$$\frac { 3 } { 10 x } + \frac { 9 } { 14 x ^ { 2 } }$$
A) $\frac { 12 } { 140 x ^ { 2 } }$
B) $\frac { 12 } { 10 x + 14 x ^ { 2 } }$
C) $\frac { 3 ( 7 x + 15 ) } { 70 x }$
D) $\frac { 3 ( 7 x + 15 ) } { 70 x ^ { 2 } }$

Question

Quizplus · Accepted Answer

To add the fractions, find a common denominator, which is $140x^2$. Convert each fraction: $\frac{3}{10x} = \frac{3 \cdot 14x}{10x \cdot 14x} = \frac{42x}{140x^2}$ and $\frac{9}{14x^2} = \frac{9 \cdot 10}{14x^2 \cdot 10} = \frac{90}{140x^2}$. Adding them gives $\frac{42x + 90}{140x^2} = \frac{3(14x + 30)}{140x^2} = \frac{3(7x + 15)}{70x^2}$.

Perform the Indicated Operations 310x+914x2\frac { 3 } { 10 x } + \frac { 9 } { 14 x ^ { 2 } }10x3​+14x29​

Perform the Indicated Operations $\frac { 3 } { 10 x } + \frac { 9 } { 14 x ^ { 2 } }$