Decide what values of the variable cannot possibly be solutions for the equation.
-$\sqrt { 2 x + 3 } + \sqrt { 4 - x } = 4$
A) $\varnothing$
B) $\{ - 3 \}$
C) $\left\{ 3 , \frac { 11 } { 9 } \right\}$
D) $\{ 3 \}$

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The Answer of Decide what values of the variable cannot possibly be solutions for the equation.
-$\sqrt { 2 x + 3 } + \sqrt { 4 - x } = 4$
A) $\varnothing$
B) $\{ - 3 \}$
C) $\left\{ 3 , \frac { 11 } { 9 } \right\}$
D) $\{ 3 \}$

Decide What Values of the Variable Cannot Possibly Be Solutions 2x+3+4−x=4\sqrt { 2 x + 3 } + \sqrt { 4 - x } = 42x+3​+4−x​=4

Decide What Values of the Variable Cannot Possibly Be Solutions $\sqrt { 2 x + 3 } + \sqrt { 4 - x } = 4$