Decide what values of the variable cannot possibly be solutions for the equation.
-$$\frac { - 5 x ^ { 2 } - 4 } { x - 4 } = \frac { - 15 x } { x - 4 } + 4$$
A) $\left\{ \frac { 4 } { 5 } , - 3 \right\}$
B) $\left\{ \frac { - 5 \pm \sqrt { 145 } } { 3 } \right\}$
C) $\{ 3 \}$
D) $\left\{ - \frac { 4 } { 5 } , 3 \right\}$

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The Answer of Decide what values of the variable cannot possibly be solutions for the equation.
-$$\frac { - 5 x ^ { 2 } - 4 } { x - 4 } = \frac { - 15 x } { x - 4 } + 4$$
A) $\left\{ \frac { 4 } { 5 } , - 3 \right\}$
B) $\left\{ \frac { - 5 \pm \sqrt { 145 } } { 3 } \right\}$
C) $\{ 3 \}$
D) $\left\{ - \frac { 4 } { 5 } , 3 \right\}$

Decide What Values of the Variable Cannot Possibly Be Solutions −5x2−4x−4=−15xx−4+4\frac { - 5 x ^ { 2 } - 4 } { x - 4 } = \frac { - 15 x } { x - 4 } + 4x−4−5x2−4​=x−4−15x​+4

Decide What Values of the Variable Cannot Possibly Be Solutions $\frac { - 5 x ^ { 2 } - 4 } { x - 4 } = \frac { - 15 x } { x - 4 } + 4$