Decide what values of the variable cannot possibly be solutions for the equation.
-$$\frac { 6 } { x + 5 } = 1 - \frac { 1 } { x - 5 }$$
A) $\varnothing$
B) $\{ 0 , - 5 \}$
C) $\{ 1,5 \}$
D) $\{ 0,7 \}$

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The Answer of Decide what values of the variable cannot possibly be solutions for the equation.
-$$\frac { 6 } { x + 5 } = 1 - \frac { 1 } { x - 5 }$$
A) $\varnothing$
B) $\{ 0 , - 5 \}$
C) $\{ 1,5 \}$
D) $\{ 0,7 \}$

Decide What Values of the Variable Cannot Possibly Be Solutions 6x+5=1−1x−5\frac { 6 } { x + 5 } = 1 - \frac { 1 } { x - 5 }x+56​=1−x−51​

Decide What Values of the Variable Cannot Possibly Be Solutions $\frac { 6 } { x + 5 } = 1 - \frac { 1 } { x - 5 }$