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A New Chocolate Company Is Estimating How Many Candy Bars r\mathrm { r }

Question 526

Multiple Choice

A new chocolate company is estimating how many candy bars per week college students will consume of their line of
products. The graph shows the probable number of candy bars students (age 18-22) will consume from year 0 to year 10.
B(x) gives the number of candy bars for boys, G(x) gives the number of candy bars for girls, and T(x) gives the total
number for both groups. Use the graph to answer the question.  A new chocolate company is estimating how many candy bars per week college students will consume of their line of products. The graph shows the probable number of candy bars students (age 18-22)  will consume from year 0 to year 10. B(x)  gives the number of candy bars for boys, G(x)  gives the number of candy bars for girls, and T(x)  gives the total number for both groups. Use the graph to answer the question.   -The radius  \mathrm { r }  of a circle of known area  \mathrm { A }  is given by  \mathrm { r } = \sqrt { \mathrm { A } / \pi } , where  \pi \approx 3.1416 . Find the radius and circumference of a circle with an area of  48.71 \mathrm { sq } \mathrm { ft } . (Round results to two decimal places.)  A)   \mathrm { r } = 15.52 \mathrm { ft } , \mathrm { C } = 97.52 \mathrm { ft }  B)   \mathrm { r } = 3.94 \mathrm { ft } , \mathrm { C } = 24.76 \mathrm { ft }  C)   \mathrm { r } = 3.94 \mathrm { ft } , \mathrm { C } = 24.76 \mathrm { sq } \mathrm { ft }  D)   \mathrm { r } = 3.94 \mathrm { ft } , \mathrm { C } = 8.86 \mathrm { ft }
-The radius r\mathrm { r } of a circle of known area A\mathrm { A } is given by r=A/π\mathrm { r } = \sqrt { \mathrm { A } / \pi } , where π3.1416\pi \approx 3.1416 . Find the radius and circumference of a circle with an area of 48.71sqft48.71 \mathrm { sq } \mathrm { ft } . (Round results to two decimal places.)


A) r=15.52ft,C=97.52ft\mathrm { r } = 15.52 \mathrm { ft } , \mathrm { C } = 97.52 \mathrm { ft }
B) r=3.94ft,C=24.76ft\mathrm { r } = 3.94 \mathrm { ft } , \mathrm { C } = 24.76 \mathrm { ft }
C) r=3.94ft,C=24.76sqft\mathrm { r } = 3.94 \mathrm { ft } , \mathrm { C } = 24.76 \mathrm { sq } \mathrm { ft }
D) r=3.94ft,C=8.86ft\mathrm { r } = 3.94 \mathrm { ft } , \mathrm { C } = 8.86 \mathrm { ft }

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