Find the center-radius form of the equation of the circle.
-center (10, 0), radius 3
A) $( x + 10 ) ^ { 2 } + y ^ { 2 } = 9$
B) $( x - 10 ) ^ { 2 } + y ^ { 2 } = 9$
C) $x ^ { 2 } + ( y + 10 ) ^ { 2 } = 3$
D) $x ^ { 2 } + ( y - 10 ) ^ { 2 } = 3$

Question

Find the center-radius form of the equation of the circle.
-center (10, 0), radius 3 
A) $( x + 10 ) ^ { 2 } + y ^ { 2 } = 9$
B) $( x - 10 ) ^ { 2 } + y ^ { 2 } = 9$
C) $x ^ { 2 } + ( y + 10 ) ^ { 2 } = 3$
D) $x ^ { 2 } + ( y - 10 ) ^ { 2 } = 3$

Quizplus · Accepted Answer

The center-radius form of a circle's equation is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. Given the center (10, 0) and radius 3, the equation becomes $(x - 10)^2 + (y - 0)^2 = 3^2$, which simplifies to $(x - 10)^2 + y^2 = 9$.

Find the Center-Radius Form of the Equation of the Circle (x+10)2+y2=9( x + 10 ) ^ { 2 } + y ^ { 2 } = 9(x+10)2+y2=9

Find the Center-Radius Form of the Equation of the Circle $( x + 10 ) ^ { 2 } + y ^ { 2 } = 9$