$$\text { If } y \text { varies directly as } x ^ { 2 } \text { and inversely as } m \text {, and } y = 4 \text { when } x = 5 \text { and } m = 2 , \text { find } y \text { when } x = 10 \text { and } m = 6 \text {. }$$
A) 0.67
B) 0.83
C) 5.33
D) 2.67

Question

Quizplus · Accepted Answer

y varies directly as x^2 and inversely as m, so y = k(x^2/m).When y = 4, x = 5, and m = 2, we have 4 = k(5^2/2), so k = 4/12.5 = 0.32.Therefore, y = 0.32(x^2/m).When x = 10 and m = 6, we have y = 0.32(10^2/6) = 5.33.

A) 067 B) 0

A) 067
B) 0