Identify the vertex of the parabola.
-$$y = 6 x ^ { 2 } - 72 x + 217$$
A) (1, 6)
B) (1, 0)
C) (6, 1)
D) (6, 0)

Question

Quizplus · Accepted Answer

The vertex of a parabola in the form $y = ax^2 + bx + c$ is given by the formula $(h, k)$, where $h = -\frac{b}{2a}$. For the given equation, $a = 6$ and $b = -72$. Thus, $h = -\frac{-72}{2 \times 6} = 6$. Substitute $x = 6$ back into the equation to find $k$: $y = 6(6)^2 - 72(6) + 217 = 1$. Therefore, the vertex is $(6, 1)$.

Identify the Vertex of the Parabola y=6x2−72x+217y = 6 x ^ { 2 } - 72 x + 217y=6x2−72x+217

Identify the Vertex of the Parabola $y = 6 x ^ { 2 } - 72 x + 217$