Use the formu $\mathrm { P } = \mathrm { Ie } ^{ kt }$ . A bacterial culture has an initial population of 10,000. If its population declines to 6000 in 6 hours, what will it be at the end of 8 hours?
A) 2531
B) 2000
C) 6000
D) 5061

Question

Quizplus · Accepted Answer

To find the population at the end of 8 hours, first determine the decay constant $ k $ using the given data: $ 6000 = 10000 \times e^{6k} $. Solving for $ k $, we get $ k \approx -0.0811 $. Then, use this $ k $ to find the population at 8 hours: $ P = 10000 \times e^{8 \times -0.0811} \approx 5061 $.

Use the Formu P=Iekt\mathrm { P } = \mathrm { Ie } ^{ kt }P=Iekt

Use the Formu $\mathrm { P } = \mathrm { Ie } ^{ kt }$