Find the dimensions of a rectangular garden with perimeter 62 yd an $220 \mathrm { yd } ^ { 2 }$
A) 20 yd by 11 yd
B) 10 yd by 22 yd
C) 20 yd by 22 yd
D) 10 yd by 11 yd

Question

Quizplus · Accepted Answer

The perimeter of a rectangle is given by $2(l + w)$ and the area by $l \times w$. For a perimeter of 62 yd, we have $2(l + w) = 62$, simplifying to $l + w = 31$. For an area of $220 \mathrm { yd } ^ { 2 }$, we have $l \times w = 220$. The only pair of factors of 220 that add up to 31 are 20 and 11, making the dimensions 20 yd by 11 yd.

Find the Dimensions of a Rectangular Garden with Perimeter 62 220yd2220 \mathrm { yd } ^ { 2 }220yd2

Find the Dimensions of a Rectangular Garden with Perimeter 62 $220 \mathrm { yd } ^ { 2 }$