Find the value of the determinant.
$\left| \begin{array} { r r r }
5 & - 2 & 3 \
0 & 8 & 5 \
0 & 0 & - 6
\end{array} \right|$
A) 240
B) -240
C) 230
D) -250

Name: Find the value of the determinant. $\left| \begin{array} { r r r } 5 & - 2 & 3 \\ 0 & 8 & 5 \\ 0 & 0 & - 6 \end{array} \right|$ A) 240 B) -240 C) 230 D) -250
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Question

Find the value of the determinant.
$\left| \begin{array} { r r r } 
5 & - 2 & 3 \
0 & 8 & 5 \
0 & 0 & - 6
\end{array} \right|$
A) 240
B)  -240 
C) 230
D)  -250

Quizplus · Accepted Answer

The determinant of a triangular matrix (either upper or lower triangular) is the product of its diagonal elements. Thus, the determinant is $5 \times 8 \times (-6) = -240$.

Find the Value of the Determinant ∣5−2308500−6∣\left| \begin{array} { r r r } 5 & - 2 & 3 \\0 & 8 & 5 \\0 & 0 & - 6\end{array} \right|​500​−280​35−6​​

Find the Value of the Determinant $\left| \begin{array} { r r r } 5 & - 2 & 3 \\0 & 8 & 5 \\0 & 0 & - 6\end{array} \right|$