A box contains 4 slips of paper, on each of which is written the number 1, 2, 3, or 4, respectively. A slip is drawn, and the number on it is noted. That slip is put aside, and another slip is drawn and the number on it noted. What is the
Probability that
a) the sum of the two numbers is 5?
b) the first number drawn is a 2 and the second number is not 5?
c) the sum of the two numbers is not 10?
A) a) $\frac { 1 } { 3 }$ b) $\frac { 1 } { 4 } \quad$ c) 1

B) a) $\frac { 1 } { 4 } \quad$ b) $\frac { 1 } { 3 } \quad$ c) 1

C) a) $\frac { 1 } { 4 }$ b) $\frac { 1 } { 3 }$ c) 0

D) a) $\frac { 1 } { 3 }$ b) $\frac { 1 } { 4 } \quad$ c) 0

Question

A box contains 4 slips of paper, on each of which is written the number 1, 2, 3, or 4, respectively. A slip is drawn, and the number on it is noted. That slip is put aside, and another slip is drawn and the number on it noted. What is the
Probability that
a) the sum of the two numbers is 5?
b) the first number drawn is a 2 and the second number is not 5?
c) the sum of the two numbers is not 10? 
A) a) $\frac { 1 } { 3 }$ b) $\frac { 1 } { 4 } \quad$ c) 1

B) a) $\frac { 1 } { 4 } \quad$ b) $\frac { 1 } { 3 } \quad$ c) 1

C) a) $\frac { 1 } { 4 }$ b) $\frac { 1 } { 3 }$ c) 0

D) a) $\frac { 1 } { 3 }$ b) $\frac { 1 } { 4 } \quad$ c) 0

Quizplus · Accepted Answer

a) To get a sum of 5, the pairs could be (1,4), (2,3), (3,2), or (4,1). Since there are 4 successful outcomes out of 12 possible outcomes (4 choices for the first draw and 3 for the second), the probability is $\frac{4}{12} = \frac{1}{3}$.b) If the first number drawn is a 2, there are 3 possible numbers that can be drawn second (1, 3, or 4), making the probability $\frac{1}{4}$ since there are 4 different scenarios for the first draw.c) Since the numbers only go up to 4, it's impossible for the sum of two numbers to be 10, making the probability of not getting a sum of 10 equal to 1.

A Box Contains 4 Slips of Paper, on Each of Which