Bruce agrees to go to work for Jim at a rate of 3¢ for the first day, 6¢ for the second day, 12¢ for the third day, 24¢ for the fourth day, and so on. What will Bruce's daily pay be on day 10, and how much total wages will he
Have earned at the end of that day?
A) Pay on day $10 = \$ 15.36$; Total pay through day $10 = \$ 30.69$
B) Pay on day $10 = \$ 30.72$; Total pay through day $10 = \$ 30.69$
C) Pay on day $10 = \$ 5.12$; Total pay through day $10 = \$ 10.23$
D) Pay on day $10 = \$ 30.72$; Total pay through day $10 = \$ 15.33$

Question

Bruce agrees to go to work for Jim at a rate of 3¢ for the first day, 6¢ for the second day, 12¢ for the third day, 24¢ for the fourth day, and so on. What will Bruce's daily pay be on day 10, and how much total wages will he
Have earned at the end of that day? 
A) Pay on day $10 = \$ 15.36$; Total pay through day $10 = \$ 30.69$
B) Pay on day $10 = \$ 30.72$; Total pay through day $10 = \$ 30.69$
C) Pay on day $10 = \$ 5.12$; Total pay through day $10 = \$ 10.23$
D) Pay on day $10 = \$ 30.72$; Total pay through day $10 = \$ 15.33$

Quizplus · Accepted Answer

Bruce's daily pay doubles each day, starting at 3¢ on day 1. On day 10, his pay is $3 \times 2^{9}$ cents = $3 \times 512$ cents = 1536 cents or $15.36. The total pay is the sum of a geometric series: $3 \times \frac{(1-2^{10})}{(1-2)}$ cents = $3 \times 1023$ cents = 3069 cents or $30.69.

Bruce Agrees to Go to Work for Jim at a Rate