Find $a _ { n } \text { and } a _ { 6 }$ for the following arithmetic sequence.
-$$a _ { 1 } = 42 , d = - 8$$
A) $a _ { n } = 42 + 8 n , a _ { 6 } = 90$
B) $a _ { n } = 42 + 8 ( n - 1 ) , a _ { 6 } = 82$
C) $a _ { n } = 42 - 8 n , a _ { 6 } = - 6$
D) $a _ { n } = 42 - 8 ( n - 1 ) , a _ { 6 } = 2$

Question

Quizplus · Accepted Answer

The formula for the nth term of an arithmetic sequence is $a_n = a_1 + d(n - 1)$, where $a_1$ is the first term and $d$ is the common difference. Substituting $a_1 = 42$ and $d = -8$ gives $a_n = 42 - 8(n - 1)$. For $a_6$, substituting $n = 6$ into the formula gives $a_6 = 42 - 8(6 - 1) = 42 - 8(5) = 42 - 40 = 2$.

Find an and a6a _ { n } \text { and } a _ { 6 }an​ and a6​

Find $a _ { n } \text { and } a _ { 6 }$