Find the confidence interval.
-A small business ships specialty homemade candies to anywhere in the world. Past
Records indicate that the weight of orders is normally distributed. Suppose a random
Sample of 16 orders is selected and each is weighed. The sample mean was found to be
110 grams with a standard deviation of 14 grams. The 90% confidence interval for the
True mean weight of orders is
A) 103.87 to 116.14 grams.
B) 86.046 to 133.954 grams.
C) 99.5 to 120.5 grams.
D) 102.55 to 117.45 grams.
E) 103.14 to 116.86 grams.

Question

Quizplus · Accepted Answer

The correct answer is A because the 90% confidence interval for the true mean weight of orders is 103.87 to 116.14 grams. This is calculated using the formula:CI = x̄ ± z * (σ / √n)where x̄ is the sample mean, z is the z-score for the desired confidence level, σ is the population standard deviation, and n is the sample size.In this case, x̄ = 110, z = 1.645 (for a 90% confidence level), σ = 14, and n = 16. Plugging these values into the formula, we get:CI = 110 ± 1.645 * (14 / √16)CI = 110 ± 1.645 * (14 / 4)CI = 110 ± 1.645 * 3.5CI = 110 ± 5.76CI = (103.87, 116.14)

Find the Confidence Interval