First, write the value(s) that make the denominator(s) zero. Then solve the equation.
-$y _ { 1 } = \frac { 9 } { x + 2 } , y _ { 2 } = \frac { 7 } { x - 2 } , y _ { 3 } = \frac { 10 } { x ^ { 2 } - 4 }$, and $y _ { 1 } - y _ { 2 } = y _ { 3 }$
A) $\{ 21 \}$
B) $\{ - 21 \}$
C) $\{ \sqrt { 57 } \}$
D) $\{ 42 \}$

Question

Quizplus · Accepted Answer

The values that make the denominators zero are $x = -2$ and $x = 2$. Solving the equation $y_1 - y_2 = y_3$ gives $x = 21$.

First, Write the Value(s) That Make the Denominator(s) Zero y1=9x+2,y2=7x−2,y3=10x2−4y _ { 1 } = \frac { 9 } { x + 2 } , y _ { 2 } = \frac { 7 } { x - 2 } , y _ { 3 } = \frac { 10 } { x ^ { 2 } - 4 }y1​=x+29​,y2​=x−27​,y3​=x2−410​

First, Write the Value(s) That Make the Denominator(s) Zero $y _ { 1 } = \frac { 9 } { x + 2 } , y _ { 2 } = \frac { 7 } { x - 2 } , y _ { 3 } = \frac { 10 } { x ^ { 2 } - 4 }$