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Choose the One Alternative That Best Completes the Statement or Answers

Question 340

Multiple Choice

Choose the one alternative that best completes the statement or answers the question. Graph ff as a solid line and f−1\mathrm { f } ^ { - 1 } as a dashed line in the same rectangular coordinate space. Use interval notation to give the domain and range of ff and f−1f ^ { - 1 } .
- f(x) =x−5f ( x ) = \sqrt { x - 5 }
Choose the one alternative that best completes the statement or answers the question. Graph f as a solid line and \mathrm { f } ^ { - 1 } as a dashed line in the same rectangular coordinate space. Use interval notation to give the domain and range of f and f ^ { - 1 } . - f ( x ) = \sqrt { x - 5 } A) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( 5 , \infty ) ; range = ( 0 , \infty ) B) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } Has no inverse. C) f domain = ( 0 , \infty ) ; range = ( - 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty ) D) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty )


A)
Choose the one alternative that best completes the statement or answers the question. Graph f as a solid line and \mathrm { f } ^ { - 1 } as a dashed line in the same rectangular coordinate space. Use interval notation to give the domain and range of f and f ^ { - 1 } . - f ( x ) = \sqrt { x - 5 } A) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( 5 , \infty ) ; range = ( 0 , \infty ) B) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } Has no inverse. C) f domain = ( 0 , \infty ) ; range = ( - 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty ) D) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty )
ff domain =(0,∞) = ( 0 , \infty ) ; range =(5,∞) = ( 5 , \infty )
f−1f ^ { - 1 } domain =(5,∞) = ( 5 , \infty ) ; range =(0,∞) = ( 0 , \infty )

B)
Choose the one alternative that best completes the statement or answers the question. Graph f as a solid line and \mathrm { f } ^ { - 1 } as a dashed line in the same rectangular coordinate space. Use interval notation to give the domain and range of f and f ^ { - 1 } . - f ( x ) = \sqrt { x - 5 } A) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( 5 , \infty ) ; range = ( 0 , \infty ) B) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } Has no inverse. C) f domain = ( 0 , \infty ) ; range = ( - 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty ) D) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty )
ff domain =(0,∞) = ( 0 , \infty ) ; range =(5,∞) = ( 5 , \infty )
f−1f ^ { - 1 } Has no inverse.
C)
Choose the one alternative that best completes the statement or answers the question. Graph f as a solid line and \mathrm { f } ^ { - 1 } as a dashed line in the same rectangular coordinate space. Use interval notation to give the domain and range of f and f ^ { - 1 } . - f ( x ) = \sqrt { x - 5 } A) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( 5 , \infty ) ; range = ( 0 , \infty ) B) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } Has no inverse. C) f domain = ( 0 , \infty ) ; range = ( - 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty ) D) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty )
ff domain =(0,∞) = ( 0 , \infty ) ; range =(−5,∞) = ( - 5 , \infty )
f−1f ^ { - 1 } domain =(−5,∞) = ( - 5 , \infty ) ; range =(0,∞) = ( 0 , \infty )

D)
Choose the one alternative that best completes the statement or answers the question. Graph f as a solid line and \mathrm { f } ^ { - 1 } as a dashed line in the same rectangular coordinate space. Use interval notation to give the domain and range of f and f ^ { - 1 } . - f ( x ) = \sqrt { x - 5 } A) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( 5 , \infty ) ; range = ( 0 , \infty ) B) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } Has no inverse. C) f domain = ( 0 , \infty ) ; range = ( - 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty ) D) f domain = ( 0 , \infty ) ; range = ( 5 , \infty ) f ^ { - 1 } domain = ( - 5 , \infty ) ; range = ( 0 , \infty )
ff domain =(0,∞) = ( 0 , \infty ) ; range =(5,∞) = ( 5 , \infty )
f−1f ^ { - 1 } domain =(−5,∞) = ( - 5 , \infty ) ; range =(0,∞) = ( 0 , \infty )

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