Find the inverse of the one-to-one function.
-$$f ( x ) = \frac { 5 } { 3 x + 7 }$$
A) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 5 } { 3 \mathrm { x } } - \frac { 7 } { 3 }$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 5 } { 3 \mathrm { y } } - \frac { 7 } { 3 }$
C) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 3 x + 7 } { 5 }$
D) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 7 } { 3 } - \frac { 5 } { 3 \mathrm { x } }$

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The Answer of Find the inverse of the one-to-one function.
-$$f ( x ) = \frac { 5 } { 3 x + 7 }$$
A) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 5 } { 3 \mathrm { x } } - \frac { 7 } { 3 }$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 5 } { 3 \mathrm { y } } - \frac { 7 } { 3 }$
C) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 3 x + 7 } { 5 }$
D) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 7 } { 3 } - \frac { 5 } { 3 \mathrm { x } }$

Find the Inverse of the One-To-One Function f(x)=53x+7f ( x ) = \frac { 5 } { 3 x + 7 }f(x)=3x+75​

Find the Inverse of the One-To-One Function $f ( x ) = \frac { 5 } { 3 x + 7 }$