Find functions f and g so that h(x) $$h ( x ) = ( f \circ g ) ( x )$$
-$$h ( x ) = \frac { 1 } { x ^ { 2 } - 8 }$$
A) $f ( x ) = 1 / x , g ( x ) = x ^ { 2 } - 8$
B) $f ( x ) = 1 / 8 , g ( x ) = x ^ { 2 } - 8$
C) $f ( x ) = 1 / x ^ { 2 } , g ( x ) = - 1 / 8$
D) $f ( x ) = 1 / x ^ { 2 } , g ( x ) = x - 8$

Question

Quizplus · Accepted Answer

The correct functions are $f(x) = 1/x$ and $g(x) = x^2 - 8$, because when $g(x)$ is plugged into $f(x)$, it results in $f(g(x)) = 1/(x^2 - 8)$, which matches $h(x)$.

Find Functions F and G So That H(x) h(x)=(f∘g)(x)h ( x ) = ( f \circ g ) ( x )h(x)=(f∘g)(x)

Find Functions F and G So That H(x) $h ( x ) = ( f \circ g ) ( x )$