Solve.
-An investment is worth $\$ 3553$ in 1991. By 1994 it has grown to $\$ 4630$. Let y be the value of the investment in the year $\mathrm { x }$, where $\mathrm { x } = 0$ represents 1991 . Write a linear equation that models the value of the investment in the year $x$.
A) $y = 359 x + 3553$
B) $y = \frac { 1 } { 359 } x + 3553$
C) $y = - 359 x + 5707$
D) $y = - 359 x + 3553$

Question

Quizplus · Accepted Answer

The value of the investment increases by $4630 - 3553 = 1077$ over 3 years (from 1991 to 1994), so the annual increase is $1077 / 3 = 359$. Thus, the equation is $y = 359x + 3553$, where $x = 0$ in 1991.

Solve -An Investment Is Worth $3553\$ 3553$3553 In 1991 by 1994 It Has Grown To In 1991

Solve
-An Investment Is Worth $\$ 3553$ In 1991 by 1994 It Has Grown To In 1991