Solve the problem.
-Solve the equation $2 x ^ { 3 } - 17 x ^ { 2 } + 38 x - 15 = 0$ given that 3 is a zero of $f ( x ) = 2 x ^ { 3 } - 17 x ^ { 2 } + 38 x - 15$
A) $\left\{ 3,5 , \frac { 1 } { 2 } \right\}$
B) $\left\{ 3 , - 5 , - \frac { 1 } { 2 } \right\}$
C) $\left\{ 3,1 , \frac { 5 } { 2 } \right\}$
D) $\left\{ 3 , - 1 , - \frac { 5 } { 2 } \right\}$

Question

Quizplus · Accepted Answer

Since 3 is a zero of the polynomial, we can use synthetic division or polynomial division to divide the polynomial by $x - 3$, which will give us a quadratic equation. Solving that quadratic equation will give us the other two roots, 5 and $\frac{1}{2}$, making the set of zeros $\{3, 5, \frac{1}{2}\}$.

Solve the Problem 2x3−17x2+38x−15=02 x ^ { 3 } - 17 x ^ { 2 } + 38 x - 15 = 02x3−17x2+38x−15=0

Solve the Problem $2 x ^ { 3 } - 17 x ^ { 2 } + 38 x - 15 = 0$