Write the equation in its equivalent logarithmic form.
-$$3 - 2 = \frac { 1 } { 9 }$$
A) $\log _ { 3 } \frac { 1 } { 9 } = - 2$
B) $\log _ { 1 / 3 } 3 = - 2$
C) $\log _ { - 2 } \frac { 1 } { 9 } = 3$
D) $\log _ { 3 } - 2 = \frac { 1 } { 9 }$

Question

Quizplus · Accepted Answer

The original equation is a mistake and seems to be a typographical error. However, assuming the intention was to express $3^x = \frac{1}{9}$, where $x = -2$, the correct logarithmic form is $\log_{3}\frac{1}{9} = -2$, which matches choice A. This is because $\frac{1}{9} = 3^{-2}$, and the logarithm base 3 of $\frac{1}{9}$ equals the exponent $-2$.

Write the Equation in Its Equivalent Logarithmic Form 3−2=193 - 2 = \frac { 1 } { 9 }3−2=91​

Write the Equation in Its Equivalent Logarithmic Form $3 - 2 = \frac { 1 } { 9 }$