Solve the problem.
-The equation $\theta _ { 2 } = \tan ^ { - 1 } ( \omega \mathrm { C } / \mathrm { G } )$ gives the phase angle of impedance in the parallel portion of a distributed constant circuit. Find $\theta _ { 2 }$ if $\omega = 310$ radians per second, $\mathrm { C } = 0.04 \mu \mathrm { F }$ per kilometer, and $\mathrm { G } = 1.22 \mu$ siemens per kilometer.
A) $85.9 ^ { \circ }$
B) $88.5 ^ { \circ }$
C) $1.5 ^ { \circ }$
D) $89.4 ^ { \circ }$

Question

Quizplus · Accepted Answer

The Answer of Solve the problem.
-The equation $\theta _ { 2 } = \tan ^ { - 1 } ( \omega \mathrm { C } / \mathrm { G } )$ gives the phase angle of impedance in the parallel portion of a distributed constant circuit. Find $\theta _ { 2 }$ if $\omega = 310$ radians per second, $\mathrm { C } = 0.04 \mu \mathrm { F }$ per kilometer, and $\mathrm { G } = 1.22 \mu$ siemens per kilometer.
A) $85.9 ^ { \circ }$
B) $88.5 ^ { \circ }$
C) $1.5 ^ { \circ }$
D) $89.4 ^ { \circ }$

Solve the Problem θ2=tan⁡−1(ωC/G)\theta _ { 2 } = \tan ^ { - 1 } ( \omega \mathrm { C } / \mathrm { G } )θ2​=tan−1(ωC/G)

Solve the Problem $\theta _ { 2 } = \tan ^ { - 1 } ( \omega \mathrm { C } / \mathrm { G } )$