Determine the phase shift of the function.
-$$y = \frac { 1 } { 2 } \sin ( \pi x + 5 )$$
A) $\frac { 5 } { \pi }$ units to the left
B) $\frac { \pi } { 5 }$ units to the right
C) $- \frac { \pi } { 5 }$ units to the left
D) 5 units to the left

Question

Quizplus · Accepted Answer

The phase shift of a sine function in the form $y = a \sin(bx + c)$ is given by $-\frac{c}{b}$. Here, $c = 5$ and $b = \pi$, so the phase shift is $-\frac{5}{\pi}$, which means $\frac{5}{\pi}$ units to the left.

Determine the Phase Shift of the Function y=12sin⁡(πx+5)y = \frac { 1 } { 2 } \sin ( \pi x + 5 )y=21​sin(πx+5)

Determine the Phase Shift of the Function $y = \frac { 1 } { 2 } \sin ( \pi x + 5 )$