Determine the amplitude or period as requested.
-Amplitude of $y = - \frac { 1 } { 3 } \sin x$
A) $\frac { 1 } { 3 }$
B) 3
C) $\frac { \pi } { 3 }$
D) $- \frac { 1 } { 3 }$

Question

Quizplus · Accepted Answer

The amplitude of a trigonometric function like $y = A \sin(x)$ or $y = A \cos(x)$ is given by the absolute value of the coefficient $A$. In this case, $A = -\frac{1}{3}$, so the amplitude is $|\,-\frac{1}{3}\,| = \frac{1}{3}$.

Determine the Amplitude or Period as Requested y=−13sin⁡xy = - \frac { 1 } { 3 } \sin xy=−31​sinx

Determine the Amplitude or Period as Requested $y = - \frac { 1 } { 3 } \sin x$