The point P(x, y) on the unit circle that corresponds to a real number t is given. Find the values of the indicated
trigonometric function at t.
-$\left( \frac { 5 } { 8 } , \frac { \sqrt { 39 } } { 8 } \right) \quad$ Find $\sin t$
A) $\frac { \sqrt { 39 } } { 8 }$
B) $\frac { 5 } { 8 }$
C) $\frac { \sqrt { 39 } } { 5 }$
D) $\frac { 5 \sqrt { 39 } } { 39 }$

Question

Quizplus · Accepted Answer

The sine of an angle in the unit circle is equal to the y-coordinate of the corresponding point, which is $\frac{\sqrt{39}}{8}$ for point P.

The Point P(x, Y) on the Unit Circle That Corresponds (58,398)\left( \frac { 5 } { 8 } , \frac { \sqrt { 39 } } { 8 } \right) \quad(85​,839​​)

The Point P(x, Y) on the Unit Circle That Corresponds $\left( \frac { 5 } { 8 } , \frac { \sqrt { 39 } } { 8 } \right) \quad$