Solve the equation on the interval [0, 2π).
-$\cos x + 2 \cos x \sin x = 0$
A) $\frac { \pi } { 2 } , \frac { 7 \pi } { 6 } , \frac { 3 \pi } { 2 } , \frac { 11 \pi } { 6 }$
B) $0 , \frac { \pi } { 2 } , \frac { 7 \pi } { 6 } , \frac { 3 \pi } { 2 }$
C) $\frac { 7 \pi } { 6 } , \frac { 11 \pi } { 6 }$
D) $\frac { 7 \pi } { 6 } , \frac { 11 \pi } { 6 } , 2 \pi$

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The Answer of Solve the equation on the interval [0, 2π).
-$\cos x + 2 \cos x \sin x = 0$
A) $\frac { \pi } { 2 } , \frac { 7 \pi } { 6 } , \frac { 3 \pi } { 2 } , \frac { 11 \pi } { 6 }$
B) $0 , \frac { \pi } { 2 } , \frac { 7 \pi } { 6 } , \frac { 3 \pi } { 2 }$
C) $\frac { 7 \pi } { 6 } , \frac { 11 \pi } { 6 }$
D) $\frac { 7 \pi } { 6 } , \frac { 11 \pi } { 6 } , 2 \pi$

Solve the Equation on the Interval [0, 2π) cos⁡x+2cos⁡xsin⁡x=0\cos x + 2 \cos x \sin x = 0cosx+2cosxsinx=0

Solve the Equation on the Interval [0, 2π) $\cos x + 2 \cos x \sin x = 0$