Express the sum or difference as a product.
-$\sin 9 x - \sin 3 x$
A) $2 \sin 3 x \cos 6 x$
B) $2 \cos 3 x \cos 6 x$
C) $2 \sin 6 x \cos 3 x$
D) $2 \sin 3 x$

Question

Quizplus · Accepted Answer

The expression $\sin 9x - \sin 3x$ can be transformed into a product using the sine subtraction formula: $\sin A - \sin B = 2 \sin \left(\frac{A-B}{2}\right) \cos \left(\frac{A+B}{2}\right)$. Applying this formula with $A = 9x$ and $B = 3x$, we get $2 \sin 3x \cos 6x$.

Express the Sum or Difference as a Product sin⁡9x−sin⁡3x\sin 9 x - \sin 3 xsin9x−sin3x

Express the Sum or Difference as a Product $\sin 9 x - \sin 3 x$