Use a graph in a [ $$\left[ - 2 \pi , 2 \pi , \frac { \pi } { 2 } \right] \text { by } [ - 3,3,1 ]$$ 3, 3, 1] viewing rectangle to complete the identity.
-$$\frac { 2 \tan \frac { x } { 2 } } { 1 + \tan ^ { 2 } \frac { x } { 2 } } = ?$$
A) $\sin x$
B) $\cos x$
C) $\sin x + 1$
D) $2 \cos x - 1$

Question

Quizplus · Accepted Answer

The given expression $\frac { 2 \tan \frac { x } { 2 } } { 1 + \tan ^ { 2 } \frac { x } { 2 } }$ simplifies to $\sin x$ using the double-angle identity for sine, which states that $\sin x = \frac{2\tan(\frac{x}{2})}{1+\tan^2(\frac{x}{2})}$.

Use a Graph in a [ [−2π,2π,π2] by [−3,3,1]\left[ - 2 \pi , 2 \pi , \frac { \pi } { 2 } \right] \text { by } [ - 3,3,1 ][−2π,2π,2π​] by [−3,3,1]

Use a Graph in a [ $\left[ - 2 \pi , 2 \pi , \frac { \pi } { 2 } \right] \text { by } [ - 3,3,1 ]$