Solve the Problem $\theta$ And Initial Velocity $v$ , Then the Horizontal Distance Traveled by the Projectile Is

Solve the problem.
-If a projectile is fired at an angle $\theta$ and initial velocity $v$ , then the horizontal distance traveled by the projectile is given by $D = \frac { 1 } { 16 } \mathrm { v } ^ { 2 } \sin \theta \cos \theta$ . Express $D$ as a function of $2 \theta$ .

A) $D = \frac { 1 } { 32 } v ^ { 2 } \sin 2 \theta$
B) $D = \frac { 1 } { 8 } v ^ { 2 } \sin 2 \theta$
C) $D = \frac { 1 } { 16 } v ^ { 2 } \sin 2 \theta$
D) $D = \frac { 1 } { 16 } v ^ { 2 } \cos 2 \theta$