Complete the identity.
-$\frac { \sin ( \alpha + \beta ) } { \sin ( \alpha - \beta ) } =$ ?
A) $\frac { \tan \alpha + \tan \beta } { \tan \alpha - \tan \beta }$
B) $\frac { \tan \alpha - \tan \beta } { \tan \alpha + \tan \beta }$
C) $\frac { \tan ( \alpha + \beta ) } { \tan \alpha - \tan \beta }$
D) $\frac { \tan \alpha - \tan \beta } { \tan ( \alpha + \beta ) }$

Question

Quizplus · Accepted Answer

Using the sine addition and subtraction formulas, and the definition of tangent as $\tan \theta = \frac{\sin \theta}{\cos \theta}$, the identity simplifies to $\frac{\tan \alpha + \tan \beta}{\tan \alpha - \tan \beta}$.

Complete the Identity sin⁡(α+β)sin⁡(α−β)=\frac { \sin ( \alpha + \beta ) } { \sin ( \alpha - \beta ) } =sin(α−β)sin(α+β)​=

Complete the Identity $\frac { \sin ( \alpha + \beta ) } { \sin ( \alpha - \beta ) } =$