Solve the problem
-Find the work done by a force of 2 pounds acting in the direction of $42 ^ { \circ }$ to the horizontal in moving an object 7 feet from $( 0,0 )$ to $( 7,0 )$.
A) $10.4 \mathrm { ft } - \mathrm { lb }$
B) $9.4 \mathrm { ft } - \mathrm { lb }$
C) $20.8 \mathrm { ft } - \mathrm { lb }$
D) $11.2 \mathrm { ft } - \mathrm { lb }$

Question

Quizplus · Accepted Answer

Work done is calculated as $W = Fd\cos(\theta)$, where $F = 2$ pounds, $d = 7$ feet, and $\theta = 42^\circ$. Thus, $W = 2 \times 7 \times \cos(42^\circ) \approx 10.4 \, \mathrm{ft-lb}$.

Solve the Problem -Find the Work Done by a Force 42∘42 ^ { \circ }42∘

Solve the Problem
-Find the Work Done by a Force $42 ^ { \circ }$