Find the Unit Vector in the Direction of v
-$$v = 3 \mathbf { i } + \mathbf { j }$$
A) $\mathbf { u } = \frac { 3 } { \sqrt { 10 } } \mathbf { i } + \frac { 1 } { \sqrt { 10 } } \mathbf { j }$
B) $\mathbf { u } = 3 \sqrt { 10 } \mathrm { i } + \sqrt { 10 } \mathrm { j }$
C) $\mathbf { u } = \frac { 3 } { \sqrt { 11 } } \mathbf { i } + \frac { 1 } { \sqrt { 11 } } \mathbf { j }$
D) $\mathbf { u } = \frac { \sqrt { 10 } } { 3 } \mathbf { i } + \sqrt { 10 } \mathbf { j }$

Question

Quizplus · Accepted Answer

The unit vector in the direction of $v = 3\mathbf{i} + \mathbf{j}$ is found by dividing $v$ by its magnitude. The magnitude of $v$ is $\sqrt{3^2 + 1^2} = \sqrt{10}$. Thus, the unit vector is $\frac{3}{\sqrt{10}}\mathbf{i} + \frac{1}{\sqrt{10}}\mathbf{j}$.

Find the Unit Vector in the Direction of V - v=3i+jv = 3 \mathbf { i } + \mathbf { j }v=3i+j

Find the Unit Vector in the Direction of V
- $v = 3 \mathbf { i } + \mathbf { j }$