Solve the problem.
-$\left( 4 , \frac { \pi } { 3 } \right) , \mathrm { r }

Question

Solve the problem.
-$\left( 4 , \frac { \pi } { 3 } \right) , \mathrm { r } < 0$ and $0 < \theta < 2 \pi$
A) $\left( - 4 , \frac { 4 } { 3 } \pi \right)$
B) $\left( - 4 , - \frac { 2 } { 3 } \pi \right)$
C) $\left( - 4 , \frac { 7 } { 3 } \pi \right)$
D) $\left( - 4 , - \frac { 5 } { 3 } \pi \right)$

Quizplus · Accepted Answer

When $r < 0$ and the angle is in the first quadrant ($\frac{\pi}{3}$), to maintain the same point in Cartesian coordinates but with $r > 0$, you add $\pi$ to the angle. Thus, $\frac{\pi}{3} + \pi = \frac{4\pi}{3}$, making the correct answer $\left( -4, \frac{4\pi}{3} \right)$.

Solve the Problem (4,π3),r<0\left( 4 , \frac { \pi } { 3 } \right) , \mathrm { r } < 0(4,3π​),r<0

Solve the Problem $\left( 4 , \frac { \pi } { 3 } \right) , \mathrm { r } < 0$