Solve the system using the inverse that is given for the coefficient matrix.
-$x + 2 y + 3 z = 12$ $x + y + z = - 5$ $2 x + 2 y + z = 1$$\quad$ The inverse of $\left[ \begin{array} { l l l } 1 & 2 & 3 \ 1 & 1 & 1 \ 2 & 2 & 1 \end{array} \right]$ is $\left[ \begin{array} { r r r } - 1 & 4 & - 1 \ 1 & - 5 & 2 \ 0 & 2 & - 1 \end{array} \right]$
A) $\{ ( - 33,39 , - 11 ) \}$
B) $\{ ( - 17,75,1 ) \}$
C) $\{ ( 48,10,1 ) \}$
D) $\{ ( - 7 , - 11 , - 9 ) \}$

Question

Quizplus · Accepted Answer

To solve the system using the inverse matrix, you multiply the inverse matrix by the constants on the right side of the equations. The calculation yields the solution $(-33, 39, -11)$.

Solve the System Using the Inverse That Is Given for the Coefficient