Multiply Matrices

-$A = \left[ \begin{array} { l l l } - 1 & - 9 & 5 \end{array} \right] , B = \left[ \begin{array} { r r r } 1 & - 5 & 9 \ 5 & 6 & 2 \ - 5 & - 9 & - 8 \end{array} \right]$
A) $[ - 71 - 94 - 67 ]$
B)
$\left[ \begin{array} { l } - 71 \ - 94 \ - 67 \end{array} \right]$
C)
$\left[ \begin{array} { r r r } - 1 & - 9 & 5 \ 1 & - 5 & 9 \ 5 & 6 & 2 \ - 5 & - 9 & - 8 \end{array} \right]$
D)
$\left[ \begin{array} { r r r } - 1 & 45 & 45 \ - 5 & - 54 & 10 \ 5 & 81 & - 40 \end{array} \right]$

Question

Multiply Matrices

-$A = \left[ \begin{array} { l l l } - 1 & - 9 & 5 \end{array} \right] , B = \left[ \begin{array} { r r r } 1 & - 5 & 9 \ 5 & 6 & 2 \ - 5 & - 9 & - 8 \end{array} \right]$
A) $[ - 71 - 94 - 67 ]$
B)
$\left[ \begin{array} { l } - 71 \ - 94 \ - 67 \end{array} \right]$
C)
$\left[ \begin{array} { r r r } - 1 & - 9 & 5 \ 1 & - 5 & 9 \ 5 & 6 & 2 \ - 5 & - 9 & - 8 \end{array} \right]$
D)
$\left[ \begin{array} { r r r } - 1 & 45 & 45 \ - 5 & - 54 & 10 \ 5 & 81 & - 40 \end{array} \right]$

Quizplus · Accepted Answer

To multiply matrices, we multiply each row of the first matrix by each column of the second matrix and sum the products. For $A \times B$, we get: $(-1*1) + (-9*5) + (5*-5) = -1 - 45 - 25 = -71$, $(-1*-5) + (-9*6) + (5*-9) = 5 - 54 - 45 = -94$, $(-1*9) + (-9*2) + (5*-8) = -9 - 18 - 40 = -67$. So, the result is $[-71, -94, -67]$.

Multiply Matrices - A) [−71−94−67][ - 71 - 94 - 67 ][−71−94−67]

Multiply Matrices

- A) $[ - 71 - 94 - 67 ]$