Solve Matrix Equations
-Let $\mathrm { A } = \left[ \begin{array} { c r } 4 & 5 \ 0 & 3 \ 9 & - 9 \end{array} \right]$ and $\mathrm { B } = \left[ \begin{array} { r r } 9 & - 9 \ - 4 & 5 \ 0 & 8 \end{array} \right] ; \quad \mathrm { B } - \mathrm { X } = 3 \mathrm {~A}$
A)
$X = \left[ \begin{array} { c c } - 3 & - 24 \ - 4 & - 4 \ - 27 & 35 \end{array} \right]$
B)
$X = \left[ \begin{array} { r r } 21 & 6 \ 4 & 14 \ 27 & - 19 \end{array} \right]$
C)
$X = \left[ \begin{array} { r r } - 3 & - 24 \ 4 & - 4 \ - 27 & 35 \end{array} \right]$
D)
$X = \left[ \begin{array} { r r } 21 & 6 \ 4 & 14 \ 9 & - 19 \end{array} \right]$

Question

Quizplus · Accepted Answer

To solve for $X$ in the equation $B - X = 3A$, we first calculate $3A$:$$3A = 3 \times \left[ \begin{array} { c r } 4 & 5 \ 0 & 3 \ 9 & - 9 \end{array} \right] = \left[ \begin{array} { c r } 12 & 15 \ 0 & 9 \ 27 & - 27 \end{array} \right]$$Then, we solve for $X$ using the equation $B - X = 3A$, which rearranges to $X = B - 3A$:$$X = \left[ \begin{array} { r r } 9 & - 9 \ - 4 & 5 \ 0 & 8 \end{array} \right] - \left[ \begin{array} { c r } 12 & 15 \ 0 & 9 \ 27 & - 27 \end{array} \right] = \left[ \begin{array} { c c } - 3 & - 24 \ - 4 & - 4 \ - 27 & 35 \end{array} \right]$$

Solve Matrix Equations -Let A=[45039−9]\mathrm { A } = \left[ \begin{array} { c r } 4 & 5 \\ 0 & 3 \\ 9 & - 9 \end{array} \right]A=​409​53−9​​

Solve Matrix Equations
-Let $\mathrm { A } = \left[ \begin{array} { c r } 4 & 5 \\ 0 & 3 \\ 9 & - 9 \end{array} \right]$