Find the solution set for the system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection.
-$$\begin{array} { l }
x = ( y + 2 ) ^ { 2 } - 1 \
( x - 2 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 1
\end{array}$$

A) $\{ ( 2 , - 2 ) \}$
B) $\{ ( - 1 , - 2 ) \}$
C) $\{ ( - 1 , - 2 ) , ( 2 , - 2 ) \}$
D) $\varnothing$

Question

Find the solution set for the system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection.
-$$\begin{array} { l } 
x = ( y + 2 ) ^ { 2 } - 1 \
( x - 2 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 1
\end{array}$$

A) $\{ ( 2 , - 2 ) \}$ 
B) $\{ ( - 1 , - 2 ) \}$ 
C) $\{ ( - 1 , - 2 ) , ( 2 , - 2 ) \}$ 
D) $\varnothing$

Quizplus · Accepted Answer

The Answer of Find the solution set for the system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection.
-$$\begin{array} { l } 
x = ( y + 2 ) ^ { 2 } - 1 \
( x - 2 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 1
\end{array}$$

A) $\{ ( 2 , - 2 ) \}$ 
B) $\{ ( - 1 , - 2 ) \}$ 
C) $\{ ( - 1 , - 2 ) , ( 2 , - 2 ) \}$ 
D) $\varnothing$

Find the Solution Set for the System by Graphing Both x=(y+2)2−1(x−2)2+(y+2)2=1\begin{array} { l } x = ( y + 2 ) ^ { 2 } - 1 \\( x - 2 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 1\end{array}x=(y+2)2−1(x−2)2+(y+2)2=1​

Find the Solution Set for the System by Graphing Both $\begin{array} { l } x = ( y + 2 ) ^ { 2 } - 1 \\( x - 2 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 1\end{array}$