Graph Hyperbolas Centered at the Origin
-$16 x^{2}-9 y^{2}=144$

A) Asymptotes: $\mathrm { y } = \pm \frac { 4 } { 3 } \mathrm { x }$
B) Asymptotes: $y = \pm \frac { 3 } { 4 } x$
C) Asymptotes: $y = \pm \frac { 3 } { 4 } x$
D) Asymptotes: $\mathrm { y } = \pm \frac { 4 } { 3 } \mathrm { x }$

Question

Graph Hyperbolas Centered at the Origin
-$16 x^{2}-9 y^{2}=144$

A) Asymptotes: $\mathrm { y } = \pm \frac { 4 } { 3 } \mathrm { x }$ 
B) Asymptotes: $y = \pm \frac { 3 } { 4 } x$ 
C) Asymptotes: $y = \pm \frac { 3 } { 4 } x$ 
D) Asymptotes: $\mathrm { y } = \pm \frac { 4 } { 3 } \mathrm { x }$

Quizplus · Accepted Answer

The Answer of Graph Hyperbolas Centered at the Origin
-$16 x^{2}-9 y^{2}=144$

A) Asymptotes: $\mathrm { y } = \pm \frac { 4 } { 3 } \mathrm { x }$ 
B) Asymptotes: $y = \pm \frac { 3 } { 4 } x$ 
C) Asymptotes: $y = \pm \frac { 3 } { 4 } x$ 
D) Asymptotes: $\mathrm { y } = \pm \frac { 4 } { 3 } \mathrm { x }$

Graph Hyperbolas Centered at the Origin - 16x2−9y2=14416 x^{2}-9 y^{2}=14416x2−9y2=144 A) Asymptotes

Graph Hyperbolas Centered at the Origin
- $16 x^{2}-9 y^{2}=144$ A) Asymptotes