Additional Concepts
-$1 - \frac { { } _ { 9 } \mathrm { P } _ { 6 } } { { } _ { 12 } \mathrm { P } _ { 9 } }$
A) $\frac { 1319 } { 1320 }$
B) $\frac { 1 } { 1320 }$
C) $\frac { 34 } { 55 }$
D) $\frac { 1321 } { 1320 }$

Question

Quizplus · Accepted Answer

The expression simplifies to $1 - \frac{9!/(9-6)!}{12!/(12-9)!}$, which equals $1 - \frac{60480}{7983360} = 1 - \frac{1}{132}$. Simplifying gives $\frac{1319}{1320}$.

Additional Concepts - 1−9P612P91 - \frac { { } _ { 9 } \mathrm { P } _ { 6 } } { { } _ { 12 } \mathrm { P } _ { 9 } }1−12​P9​9​P6​​

Additional Concepts
- $1 - \frac { { } _ { 9 } \mathrm { P } _ { 6 } } { { } _ { 12 } \mathrm { P } _ { 9 } }$