Solve the problem.
-A person puts $29 into a bank account on January 1, $39 on February 1, $49 on March 1, and so forth. How much has the person put into the bank account by December 30?
A)$1008
B)$1068
C)$2016
D)$834

Question

Quizplus · Accepted Answer

The person deposits an increasing amount each month, starting from $29 in January and increasing by $10 each month. The sequence of deposits is an arithmetic sequence with the first term $29 and the common difference $10. The 12th term (December) is $29 + 11*$10 = $139. The sum of the deposits is the sum of the first 12 terms of this arithmetic sequence, which is (12/2) * (29 + 139) = 6 * 168 = $1008.

Solve the Problem. -A Person Puts $29 into a Bank Account on January