Write a formula for the general term (the nth term) of the arithmetic sequence. Then use the formula for $$\mathbf { a } _ { \mathbf { n } }$$ to find $$a _ { 20 }$$ , the 20th term of the sequence.
-$$a _ { n } = a _ { n - 1 } - 6 , a _ { 1 } = 35$$
A) $a _ { n } = - 6 n + 41 , a _ { 20 } = - 79$
B) $\mathrm { a } _ { \mathrm { n } } = 35 \mathrm { n } + 41 , \mathrm { a } _ { 20 } = 741$
C) $a _ { n } = - 6 n + 29 , a _ { 20 } = - 91$
D) $a _ { n } = 29 n + 35 , a _ { 20 } = 615$

Question

Quizplus · Accepted Answer

The formula for the nth term of an arithmetic sequence is $a_n = a_1 + (n - 1)d$, where $d$ is the common difference. Given $a_1 = 35$ and $d = -6$, the formula becomes $a_n = 35 + (n - 1)(-6) = -6n + 41$. Substituting $n = 20$ gives $a_{20} = -6(20) + 41 = -79$.

Write a Formula for the General Term (The Nth Term) an\mathbf { a } _ { \mathbf { n } }an​

Write a Formula for the General Term (The Nth Term) $\mathbf { a } _ { \mathbf { n } }$