Write the first four terms of the sequence whose general term is given.
-$$a _ { n } = \frac { n + 1 } { 2 n - 1 }$$
A) $2,1 , \frac { 4 } { 5 } , \frac { 5 } { 7 }$
B) $2 , - 1 , \frac { 4 } { 5 } , \frac { 5 } { 7 }$
C) $- 2,1 , \frac { 4 } { 5 } , \frac { 5 } { 7 }$
D) $- 2 , - 1 , \frac { 4 } { 5 } , \frac { 5 } { 7 }$

Question

Quizplus · Accepted Answer

To find the first four terms of the sequence, substitute $n = 1, 2, 3, 4$ into the given formula $a_n = \frac{n + 1}{2n - 1}$:- For $n = 1$, $a_1 = \frac{1 + 1}{2 \cdot 1 - 1} = \frac{2}{1} = 2$- For $n = 2$, $a_2 = \frac{2 + 1}{2 \cdot 2 - 1} = \frac{3}{3} = 1$- For $n = 3$, $a_3 = \frac{3 + 1}{2 \cdot 3 - 1} = \frac{4}{5}$- For $n = 4$, $a_4 = \frac{4 + 1}{2 \cdot 4 - 1} = \frac{5}{7}$

Write the First Four Terms of the Sequence Whose General an=n+12n−1a _ { n } = \frac { n + 1 } { 2 n - 1 }an​=2n−1n+1​

Write the First Four Terms of the Sequence Whose General $a _ { n } = \frac { n + 1 } { 2 n - 1 }$