Find an equation for the line with the given properties.
-Perpendicular to the line $y = - 3 x + 4$; containing the point $( - 4,3 )$
A) $y = \frac { 1 } { 3 } x + \frac { 13 } { 3 }$
B) $y = 3 x + \frac { 13 } { 3 }$
C) $y = - \frac { 1 } { 3 } x + \frac { 13 } { 3 }$
D) $y = - 3 x + \frac { 13 } { 3 }$

Question

Quizplus · Accepted Answer

The slope of the given line is -3. For a line to be perpendicular to it, its slope must be the negative reciprocal, which is $1/3$. Using the point-slope form of a line, $y - y_1 = m(x - x_1)$, with $m = 1/3$ and $(x_1, y_1) = (-4, 3)$, we find the equation of the line to be $y = \frac{1}{3}x + \frac{13}{3}$.

Find an Equation for the Line with the Given Properties y=−3x+4y = - 3 x + 4y=−3x+4

Find an Equation for the Line with the Given Properties $y = - 3 x + 4$