Solve the problem.
-Find the area of the right triangle $\mathrm { ABC }$ with $\mathrm { A } = ( - 2,7 ) , \mathrm { B } = ( 7 , - 1 ) , \mathrm { C } = ( 3,9 )$.
A) $\frac { \sqrt { 29 } } { 2 }$ square units
B) 29 square units
C) 58 square units
D) $\frac { \sqrt { 58 } } { 2 }$ square units

Question

Quizplus · Accepted Answer

The area of a triangle with vertices $(x_1, y_1)$, $(x_2, y_2)$, $(x_3, y_3)$ is given by $\frac{1}{2} \left| x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) \right|$. Substituting the given points, the area is 29 square units.

Solve the Problem ABC\mathrm { ABC }ABC With A=(−2,7),B=(7,−1),C=(3,9)\mathrm { A } = ( - 2,7 ) , \mathrm { B } = ( 7 , - 1 ) , \mathrm { C } = ( 3,9 )A=(−2,7),B=(7,−1),C=(3,9)

Solve the Problem $\mathrm { ABC }$ With $\mathrm { A } = ( - 2,7 ) , \mathrm { B } = ( 7 , - 1 ) , \mathrm { C } = ( 3,9 )$