For the given functions f and g, find the requested function and state its domain.
-$$f ( x ) = \frac { 7 x - 6 } { 6 x - 1 } ; g ( x ) = \frac { 4 x } { 6 x - 1 }$$
Find $f + g$.
A) $( \mathrm { f } + \mathrm { g } ) ( \mathrm { x } ) = \frac { 11 \mathrm { x } - 6 } { 6 \mathrm { x } - 1 } ; \left\{ \mathrm { x } \mid \mathrm { x } \neq \frac { 1 } { 6 } \right\}$
B) $( f + g ) ( x ) = \frac { 11 x - 6 } { 6 x - 1 } ; \{ x \mid x \neq 0 \}$
C) $( f + g ) ( x ) = \frac { 11 x - 6 } { 6 x - 1 } ; \left\{ x \mid x \neq \frac { 1 } { 6 } , x \neq \frac { 6 } { 11 } \right\}$
D) $( \mathrm { f } + \mathrm { g } ) ( \mathrm { x } ) = \frac { 3 \mathrm { x } + 6 } { 6 \mathrm { x } - 1 } ; \left\{ \mathrm { x } \mid \mathrm { x } \neq \frac { 1 } { 6 } \right\}$

Question

Quizplus · Accepted Answer

To find $f + g$, add the functions $f(x) = \frac{7x - 6}{6x - 1}$ and $g(x) = \frac{4x}{6x - 1}$ together. The result is $\frac{7x - 6 + 4x}{6x - 1} = \frac{11x - 6}{6x - 1}$. The domain excludes $x = \frac{1}{6}$ because $6x - 1 = 0$ leads to division by zero.

For the Given Functions F and G, Find the Requested f(x)=7x−66x−1;g(x)=4x6x−1f ( x ) = \frac { 7 x - 6 } { 6 x - 1 } ; g ( x ) = \frac { 4 x } { 6 x - 1 }f(x)=6x−17x−6​;g(x)=6x−14x​

For the Given Functions F and G, Find the Requested $f ( x ) = \frac { 7 x - 6 } { 6 x - 1 } ; g ( x ) = \frac { 4 x } { 6 x - 1 }$