Solve the system of equations by using substitution.
-$$\left\{ \begin{array} { l }
3 x + y = 13 \
2 x + 9 y = - 8
\end{array} \right.$$
A) $x = 5 , y = 2$
B) $x = - 5 , y = 2$
C) $x = 5 , y = - 2$
D) $x = - 5 , y = - 2$

Question

Solve the system of equations by using substitution.
-$$\left\{ \begin{array} { l } 
3 x + y = 13 \
2 x + 9 y = - 8
\end{array} \right.$$
A) $x = 5 , y = 2$
B) $x = - 5 , y = 2$
C) $x = 5 , y = - 2$
D) $x = - 5 , y = - 2$

Quizplus · Accepted Answer

First, solve the first equation for $y$: $y = 13 - 3x$. Then substitute this expression for $y$ in the second equation: $2x + 9(13 - 3x) = -8$. Simplify and solve for $x$, which gives $x = 5$. Substitute $x = 5$ back into $y = 13 - 3x$ to find $y = -2$.

Solve the System of Equations by Using Substitution {3x+y=132x+9y=−8\left\{ \begin{array} { l } 3 x + y = 13 \\2 x + 9 y = - 8\end{array} \right.{3x+y=132x+9y=−8​

Solve the System of Equations by Using Substitution $\left\{ \begin{array} { l } 3 x + y = 13 \\2 x + 9 y = - 8\end{array} \right.$