Find the nth term of the geometric sequence.
-$$3 , - \frac { 3 } { 5 } , \frac { 3 } { 25 } , - \frac { 3 } { 125 } , \frac { 3 } { 625 }$$
A) $a _ { n } = 3 \cdot \left( - \frac { 1 } { 25 } \right) ^ { n - 1 }$
B) $a _ { n } = 3 \cdot \left( - \frac { 1 } { 5 } \right) ^ { n - 1 }$
C) $a _ { n } = 3 \cdot \left( - \frac { 1 } { 5 } \right) ^ { n }$
D) $a _ { n } = 3 \cdot \left( - \frac { 1 } { 5 } \right) ^ { n + 1 }$

Question

Quizplus · Accepted Answer

The common ratio between terms is $-\frac{1}{5}$, and the first term is 3, so the nth term is given by $a_n = 3 \cdot \left(-\frac{1}{5}\right)^{n-1}$.

Find the Nth Term of the Geometric Sequence 3,−35,325,−3125,36253 , - \frac { 3 } { 5 } , \frac { 3 } { 25 } , - \frac { 3 } { 125 } , \frac { 3 } { 625 }3,−53​,253​,−1253​,6253​

Find the Nth Term of the Geometric Sequence $3 , - \frac { 3 } { 5 } , \frac { 3 } { 25 } , - \frac { 3 } { 125 } , \frac { 3 } { 625 }$