Write out the sum. Do not evaluate.
-$$\sum _ { k = 1 } ^ { 4 } \left( k ^ { 2 } - 4 k - 3 \right)$$
A) $1 - 6 - 7 - 6$
B) $- 6 - 7 - 6 - 3$
C) $- 6 - 7 - 6 - 3 + \ldots$
D) $- 6 + 7 - 6 + 3$

Name: Write out the sum. Do not evaluate. -\[\sum _ { k = 1 } ^ { 4 } \left( k ^ { 2 } - 4 k - 3 \right)\] A) $1 - 6 - 7 - 6$ B) $- 6 - 7 - 6 - 3$ C) $- 6 - 7 - 6 - 3 + \ldots$ D) $- 6 + 7 - 6 + 3$
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Question

Quizplus · Accepted Answer

The expression inside the sum is $k^2 - 4k - 3$. Plugging in $k = 1, 2, 3, 4$, we get the terms $-6, -7, -6, -3$.

Write Out the Sum ∑k=14(k2−4k−3)\sum _ { k = 1 } ^ { 4 } \left( k ^ { 2 } - 4 k - 3 \right)k=1∑4​(k2−4k−3)

Write Out the Sum $\sum _ { k = 1 } ^ { 4 } \left( k ^ { 2 } - 4 k - 3 \right)$